Answer to Question #215466 in Mechanical Engineering for Aron

Question #215466
Assume that a 2 kg of a certain gas with R=0.4305 kJ/kg-K undergoes a process that results in these changes: ΔU=1458.01 kJ, ΔH=2189.13 kJ. What is the temperature change?
1
Expert's answer
2021-07-12T03:36:37-0400

m = 2kg

R = 0.4305 kJ/kg.K

∆U = 1458.01 kJ

∆H = 2189.13 kJ


"\u2206H = \u2206U -mR\u2206T\\\\\n2189.13 = 1458.01 - 2(0.4305)\u2206T\n\\\\ 731.12 =0.861\u2206T\\\\\n\u2206T = 849.15K\n"

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