m = 2kg
R = 0.4305 kJ/kg.K
∆U = 1458.01 kJ
∆H = 2189.13 kJ
"\u2206H = \u2206U -mR\u2206T\\\\\n2189.13 = 1458.01 - 2(0.4305)\u2206T\n\\\\ 731.12 =0.861\u2206T\\\\\n\u2206T = 849.15K\n"
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