Question #200273

An epicyclic reduction gear, as shown in Fig. 13.38, has a shaft A fixed to arm B. The arm B has a pin fixed to its outer end and two gears C and E which are rigidly fixed, revolve on this pin. Gear C meshes with annular wheel D and gear E with pinion F. G is the driver pulley and D is kept stationary.

The number of teeth are : D = 80 ; C = 10 ; E = 24 and F = 18. If the pulley G runs at 200 r.p.m. ; find the speed of shaft A.

Expert's answer

Consider gear G , then y+x=200 \implies y=200-x

Gear D is staionary So, y-\frac{-18+x}{24*8}=0 \implies 200-x=\frac{3}{32}x \implies x=182.857

Shaft A is fixed to arm B

Arm B , N=y

N_{B }=200-x

N_{B }=200-182.857=17.14 rpm

Therefore, N_{B }=N_{A }=17.14 rpm

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