Question #194386

Figure 1 shows a layer of oil (8.95 kN/m3), the thickness of 0.3 mm, between two parallel

flat plates. The upper plate is pulled across the bottom plate with a cable connected to

a winch. The upper plate moves with a velocity of 0.05 m/s. The area of contact between

the upper plate and the oil is 1.5 m2. Determine the kinematic viscosity of the oil if the

torque acting on the winch drum should not exceed 24.5 x 10-3 Nm. Take the drum

diameter as 50 mm.

Expert's answer

Data:

Weight density of oil = w=8.95 kN/m^{3}

Mass density( )==908.16 Kg/m^{3}

Thickness of oil (y)=0.3 ×10^{-3} m

Velocity of upper plate(V)=0.05 m/s

Area of plate(A)=1.5 m^{2}

Torque acting on drum(T)=24.5×10^{-3} N-m

Radius of drum (r)= 25 ×10^{-3}m

Solution:

Let F is the force acting on plate through cable and is the kinematic viscosity of oil.

We know that,

Assuming oil to be newtonian fluid,

908.16=3.56

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