Answer to Question #189459 in Mechanical Engineering for bibi

Question #189459

A frictionless piston-cylinder device contains 8 kg of superheated water vapor at 500 kPa and 300oC. Steam is now cooled at constant pressure until 70 percent of it, by mass condenses. Determine the work done and heat transfer during this process.

Expert's answer

The superheated steam at pressure, P_1=500kPa

Temperature, T_1= 300^0 C

mass, m=8 kg

Therefore, The enthalpy at initial state= H_1=m*h_1=8*(3064.6)=24516.8 kJ

If it is cooled at the same pressure, steam becomes saturated at temp T_2=152^0 C.

At P_2=500kPa, h_f=640.09 kJ/kg, h_g=2748.01 kJ/Kg

The enthalpy of saturated steam H_2 =m*h_2=mh_g=8*2748.01=21984.08 kJ

If 70% of steam is condensed at state-3, the dryness fraction at state-3 is X=0.3.

Therefore enthalpy of steam at state -3 is given by

H_3=m(hf+X(hg-hf))=10179.4 kJ

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