Answer to Question #182203 in Mechanical Engineering for luke

Question #182203

A spring extends by 5 centimeters when loaded vertically with 2.5kg of weight. A new weight of 2kg was attached to it and was displaced 6cm from its new equilibrium position and was released from rest. How long will it take for the mass to return to its point of release for the second time in seconds?


1
Expert's answer
2021-04-22T07:23:28-0400

"m \n_\n1\n\n\u200b\t\n\n =2.5kg\\\\\n\nF \n_\n1\n\n\u200b\t\n\n =2.5\u00d79.81= 24.525N\\\\\n\nx \n\n_1\n\n\u200b\t\n\n =5cm=0.05m"


"k = \\dfrac{F_1}{x_1} =\\dfrac{2.5\u00d79.81}{0.05}= 490.5N\/m"



"m_n = 2kg"

"x_n = 0.06 m"


"k_n =\\dfrac{F_n}{x_n} =\\dfrac{2\u00d79.81}{0.06}= 327N\/m"


frequency of vibration "= \\dfrac{1}{2\u03c0}\\sqrt{\\dfrac{k_n}{m_n}}"


"= \\dfrac{1}{2\u03c0}\\sqrt{\\dfrac{327}{2}}= 2.035\\ Hz"

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS