Question #180916

The gas equation is PV = nRT. If P the pressure is 2.0 atm, V the volume of the gas is 6 m3, R the gas constant is 0.08206 m3 atm mole-1 K-1 and T is 300 degrees Kelvin, what are the units of n and what is its numerical value?

Expert's answer

**Q180916**

The gas equation is PV = nRT. If P the pressure is 2.0 atm, V the volume of the gas is 6 m^{3}, R the gas constant is 0.08206 m^{3} atm mole^{-1} K^{-1} and T is 300 degrees Kelvin, what are the units of n and what is its numerical value?

**Solution: **

please check the value of gas constant, R in the question again

I will first solve the problem using the information given in the problem.

Next I will solve the problem using correct value of 'R' .

Pressure, P = 2.0 atm.

Volume, V = 6.0 m^{3}.

Gas constant, R = 0.08206 m^{3}.atm/mol.K

Temperature, T = 300 K

plug all this information in the ideal gas equation, PV = nRT.

**The units of n is 'mol' and the numerical value is 0.487. **

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I will suggest you to check the question again.

The proper value of Gas constant ' R' is 8.206 *10^{-5} m^{3}.atm/mol.K

Now I will solve the problem, using R = 8.206 *10^{-5} m^{3}.atm/mol.K

Pressure, P = 2.0 atm.

Volume, V = 6.0 m^{3}.

Gas constant, R = 8.206 *10^{-5} m^{3}.atm/mol.K

Temperature, T = 300 K

plug all this information in the ideal gas equation, PV = nRT.

If you use the correct value of Gas constant 'R' then we will get

**The units of n is 'mol' and the numerical value is 487. **

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