Determine the root of f(x)=x3-6x2+11x-6.1 using the Newton-Rapson Method(three iterations, xi=3.5)
Given
"f(x)=x^3-6x^2+11x-6"
"f'(x)=3x^2-12x+11"
"x_0=3.5"
Root is : "x=3.000003"
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