A spring extends 2 inches when loaded vertically with 4 lbs. This weight was pulled further down by 3 inches an was released from rest. Determine the frequency of vibration in rad per second
where; k is the spring constant.
f is the force applied.
x is the extension on the spring.
4lbs = 1.81 kgs
2inches = 0.0508 m
3inches = 0.0762 m
k= 18.1Newtons/ 0.0508m
= 356.3 N/m
force required to extend the spring to a further 3inches (0.0762m)
= 356.3 N/m *0.0762
= 11.455 rads/sec