Answer to Question #172818 in Mechanical Engineering for clar

Question

A 333 - g ball is attached to a string 1.73 m long. The ball is spinning at a constant velocity of 5.4 rev/s. Determine the acceleration of the object.

Answer 1

constant velocity= 5.4 rev/s

angular velocity = $\omega= 2\times 3.14 \times 5.4=33.912 \frac{rad}{s}$

acceleration of body= $r \omega^2= 1.73 \times (33.912)^2=1989.54 \frac{m}{s^2}$