# Answer to Question #172504 in Mechanical Engineering for isaac

Question #172504

) A bar of 20 mm diameter is tested in tension. When a load of 38 kN was applied

extension of 0.12 mm was measured over a length of 200 mm and contraction in

diameter was 0.004 mm. If Young’s modulus is 2 × 105 N/mm2

then the value of

modulus of rigidity is??

1
2021-03-18T03:38:03-0400

Diameter of bar is 20 mm, Load = 38 kN, extension =0.12 mm, length=200 mm,

contraction diameter=0.004 mm, "E= 2 \\times 10^5" ,

lateral strain= "\\frac{\\delta d}{d}=\\frac{0.004}{20}=0.0002" ,

longitudinal strain="\\frac{\\delta l}{l}=\\frac{.12}{200}=0.0006"

poisson ratio="\\frac{lateral strain}{longitudinal strain}= \\frac{0.0002}{0.0006}=0.333"

We know that relation between Modulus of rigidity and Young's modulus

"E= 2G(1+\\nu)"

"2\\times 10 ^5 = 2G(1+0.333)"

G= "0.75\\times 10 ^5= 7.5 \\times 10 ^4 \\frac{N}{mm^2}"

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!