Question #169585

A 10.000-in-diameter plunger slides in a 10.006-in-diameter cylinder, the annular space being filled with oil having a kinematic viscosity of 0.004 ft2/s and specific gravity of 0.85. If the plunger moves at 0.6ft/s, find the force, in lbf, when 9 ft is engaged in the cylinder

Expert's answer

"Plunger \\space diameter=10.000 in"

"Cylinder \\space diameter=10.006 in"

"Kinematic \\space viscosity =0.004ft^2\/s"

"G=0.85"

Plunger moves 0.6ft/s

"\\rho=\\mu(\\frac{du}{dx}), \\delta=\\frac{0.85 \\times62.4}{32.2}=1.647 plunges\/ft^3"

"\\mu=1.647 \\times0.004=0.006588 lb.s\/ft^2"

"du=\\frac{10.006-10.000}{2}\/12=0.000250 ft"

"Z=0.006588(0.6\/0.00025)=15.81 lb\/ft^2"

"F_f=ZA=15.81\\times(9 \\times \\pi(\\frac{10}{12})=372.5 lb"

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