Question #156518

Find c_{v} and c_{p} for a certain fluid if the properties are related as follows: u = (196 + 0.718t) KJ/kg_{m} and pv = [0.287(t^{o}c + 273)] where v is in m^{3}/kg_{m} and p is in KN/m^{2}.

Expert's answer

U = (196 + 0.718t) KJ/kg

C_{v}="\\frac{dU}{dT}=\\frac{d(196+0.718t)}{dT}"

"C_v=0.718 \\frac{kJ}{kgK}"

PV=[0.287(t^{o}c + 273)]

"C_p=C_v+P(\\frac{\\delta V}{dT})"

"C_p=0.718+.287=1.005 \\frac{Kj}{kgK}"

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