Question

Find c_v and c_p for a certain fluid if the properties are related as follows: u = (196 + 0.718t) KJ/kg_m and pv = [0.287(t^oc + 273)] where v is in m³/kg_m and p is in KN/m².

Answer 1

U = (196 + 0.718t) KJ/kg

C_v=$\frac{dU}{dT}=\frac{d(196+0.718t)}{dT}$

$C_v=0.718 \frac{kJ}{kgK}$

PV=[0.287(t^oc + 273)] 

$C_p=C_v+P(\frac{\delta V}{dT})$

$C_p=0.718+.287=1.005 \frac{Kj}{kgK}$