Answer to Question #154897 in Mechanical Engineering for Nigel

Question

QUESTION 3

a. A certain engine develops a torque of 120 Nm while running at a speed of 3000 rev/min. Calculate the brake power. Take pie =3,142. (5)

b. An indicator diagram taken from a single-cylinder 4-stroke engine has an effective area of 600 mm2

If the base length of the indicator diagram is 60 mm and the constant is 80 kPa/mm calculate the indicated mean effective pressure

Answer 1

power =$\tau \times W$

$= \tau\times \frac{2\pi N}{60}$

$= 120\times \frac{2\times3.142\times 3000}{60}$

= 37704 watt

= 37.704 KW