Answer to Question #153224 in Mechanical Engineering for Amrish

Question #153224

Determine the smallest size of hole that can be punched in 12 mm thick MS 

plate having ultimate shear stress of 390 N/mm2 , if permissible crushing 

stress for the punch material is 2.4 kN/mm2.


1
Expert's answer
2021-01-06T06:04:12-0500

Ultimate shear stress=\tau_u= 390 N/mm2, thickness= 12mm,


Permissible crushing stress=2.4 kN/mm2


Axial shear force= (\frac{\pi d^2}{4})\tau= F ,In case of crushing


F=\pi dt \times \sigma_c as we know that in case of small size both force will be same


\pi dt \sigma_c=\frac{\pi d^2}{4}\times \tau_u


12 \times 2400= \frac{d}{4}\times 390


d=295.38 mm


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