Answer to Question #148768 in Mechanical Engineering for Drew

Question

If 6 liters of a gas at a pressure of 100 kPaa are compressed reversibly according tp PV2 = C until the volume becomes 2 liters, find (a) the final pressure in kPaa, and (b) the work in kJ.

Answer 1

Given V1= 6 liters

$V1= 0.006 mt^3$

P1=100 Kpa

V2= 2 liters=$0.002 mt^3$

Process $P\times V^2=C$

$P1\times V1^2 = P2\times V2^2$

$100\times 6^2 = P2\times 2^2$

$P2 = 900$ Kpa(final pressure)

work done = Pdv

Work done during polytrophic process n is given by

$W = \frac{P1 \times V1 - P2 \times V2}{n-1}$

$W = \frac{100\times 0.006 - 900 \times 0.002}{2-1}$

$W = - 1.2$ Kj

here negative sign represents work done on the system