Question #143096

what is the final pressure of an ideal gas at 50 psig and 90 F, heated in a closed container to 150 F?expres your answer in psia

Expert's answer

Absolute pressure = Gauge pressure - atmospheric pressure.

"T_1=90F =\\frac{(90-32)*5}{9}+273=305 K"

"P_1=50 psig =(50+14.5) = 64.5 psi absolute"

"T_2=150F =\\frac{(150-32)*5}{9}+273=338.7 K"

"\\frac{P_1}{T_1}=\\frac{P_2}{T_2}\n\\implies P_2=\\frac{P_1*T_2}{T_1}"

"P_2=\\frac{338.7*64.5}{305.4}=71.53 abs=71.53 psia"

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