Answer to Question #131072 in Mechanical Engineering for Smith

Question

An object starts from rest with an acceleration of 5m/s2 along a straight line. Find the speed and distance travelled after 6 seconds what use the average speed during those
6 seconds?

Answer 1

Let initial velocity (v₀)=0 m/s

Acceleration (a)=5 m/s²

Velocity after 6 seconds

v6=v_o+a x t =5x6=30 m/s

Velocity after 5 seconds

v₅=v_o+a x t =5x5=25 m/s

Average speed during 6^th second

=1/2(v₅+v₆)=27.5 m/s

Distance travelled after 6 second

d=v_o x t +1/2(a)x t² =90 m