Question #131072

An object starts from rest with an acceleration of 5m/s2 along a straight line. Find the speed and distance travelled after 6 seconds what use the average speed during those

6 seconds?

6 seconds?

Expert's answer

Let initial velocity (v_{0})=0 m/s

Acceleration (a)=5 m/s^{2}

Velocity after 6 seconds

v6=v_{o}+a x t =5x6=30 m/s

Velocity after 5 seconds

v_{5}=v_{o}+a x t =5x5=25 m/s

Average speed during 6^{th }second

=1/2(v_{5}+v_{6})=27.5 m/s

Distance travelled after 6 second

d=v_{o} x t +1/2(a)x t^{2} =90 m

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