Question #128450

Two kg of saturated water at 125 kPa is completely vaporized. Calculate the volume (a)before and (b) after. Ans. (a)0.002 m3 (b)2.76 m3

Expert's answer

Mass of saturated water(m)= 2kg

Saturation pressure (p)=125kPa=0.125 MPa

From steam table , at p=0.125MPa, the specific volume of saturated water(v) = 0.001048 M3/kg

And specific volume of saturated steam(vg)=1.3768m3/kg

Therefore, volume of saturated water(Vf)=m.vf=2x0.001048=0 .00209 m3.

And the volume of saturated steam (Vg)=m.vg=2x1.3768=2.7567 m3

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