Answer to Question #128450 in Mechanical Engineering for Afra Syab

Question

Two kg of saturated water at 125 kPa is completely vaporized. Calculate the volume (a)before and (b) after. Ans. (a)0.002 m3 (b)2.76 m3

Answer 1

Mass of saturated water(m)= 2kg

Saturation pressure (p)=125kPa=0.125 MPa

From steam table , at p=0.125MPa, the specific volume of saturated water(v) = 0.001048 M3/kg

And specific volume of saturated steam(vg)=1.3768m3/kg

Therefore, volume of saturated water(Vf)=m.vf=2x0.001048=0 .00209 m3.

And the volume of saturated steam (Vg)=m.vg=2x1.3768=2.7567 m3