Answer to Question #128450 in Mechanical Engineering for Afra Syab

Question #128450
Two kg of saturated water at 125 kPa is completely vaporized. Calculate the volume (a)before and (b) after. Ans. (a)0.002 m3 (b)2.76 m3
1
Expert's answer
2020-08-05T05:23:40-0400

Mass of saturated water(m)= 2kg

Saturation pressure (p)=125kPa=0.125 MPa

From steam table , at p=0.125MPa, the specific volume of saturated water(v) = 0.001048 M3/kg

And specific volume of saturated steam(vg)=1.3768m3/kg

Therefore, volume of saturated water(Vf)=m.vf=2x0.001048=0 .00209 m3.

And the volume of saturated steam (Vg)=m.vg=2x1.3768=2.7567 m3



Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS