Question #128449

Determine the final volume of a mixture of water and steam if 3 kg of water is heated at a constant pressure until the quality is 60 percent. The pressure is (a)25 kPa and (b)270 kPa.

Ans. (a) 11.6 mZ (h)1.24 m3

Ans. (a) 11.6 mZ (h)1.24 m3

Expert's answer

a) The pressure (p)=25kPa=0.025MPa

Mass(m)=3kg

quality (X)= 0.60

From steam table at P=0.025MPa

Specific volume of saturated water (vf)=0.001019m3/kg

Specific volume of saturated steam (vg)=6.4353 m3/kg

Therefore, the volume of steam having X=0.6 is given by

V=m[vf+X(vg-vf)]

=3[0.001019+0.6(6.4353-0.001019)]

= 11.58m3.

b)The pressure (p)=270kPa=0.270 MPa

Mass(m)=3kg

quality (X)= 0.60

From steam table at P=0.270 MPa

Specific volume of saturated water (vf)=0.001069m3/kg

Specific volume of saturated steam (vg)=0.66865 m3/kg

Therefore, the volume of steam having X=0.6 is given by

V=m[vf+X(vg-vf)]

=3[0.001069+0.6(0.66865-0.001069)]

=1.2048m3

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