Question #124787

A fluid at 0.7 bar occuping 0.09m^3 is compressed reversibly to a pressure of 3.5 bar according to the law pv^n=constant.The fluid is then heated reversibly at constant volume until the pressure is 4bar;the specific volume is then 0.5 m^3/kg.A reversible expansion according to a law pv^2=constant restore the fluid in its initial state.Sketch the cycle on ap-v diagram and calculte (i)the mass of fluid present (ii)the value of n in the first process (iii)the net work of the cycle

Expert's answer

,

specific volume= then reversible expansion takes place to reverse the process

For process 3-1

here,

(i) mass of fluid= ,v= specific volume

mass of fluid= kg

(ii)

Taking log both sides

n=\frac{-0.69897}{0.0774}

(iii) Area under graph =

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