Question #124345

FIND THE SPECIFIC VOLUME ENTHALPY INTERNAL ENERGY AND ENTROPY OF WET STEAM AT 20 BAR PRESSURE ANO DRYNESS FRACTION OF 0.8

NOTE : AT 20 BAR Values To be TAKEN FROM STEAM TABLE

NOTE : AT 20 BAR Values To be TAKEN FROM STEAM TABLE

Expert's answer

The Dryness fraction(x) of the wet steam=0.8

The pressure of wet steam(P)=20 bar=2 MPa

The saturation properties of wet steam at 2 MPa is given in the steam table as-

v_{f}= 0.0012 m3/kg v_{fg}= (0.0996-0.0012)=0.0984 m3/kg

h_{f}=908.5 kJ/kg h_{fg}= 1889.8kJ/kg

u_{f}= 906.15 kJ/kg u_{fg}= (2599.1-906.15) =1692.95 kJ/Kg

s_{f}= 2.4468 kJ/kg-K s_{fg}= 3.8923 KJ/kg-K

Specific volume at x=0.8 => v=vf+x.vfg=0.07992 m3/kg

Specific enthalpy at x=0.8 => h=hf+x.hfg= 2420.34 kJ/kg

Specific internal energy at x=0.8 =>u=uf+x.ufg=2260.51 kJ/Kg

Specific entropy at x=0.8 => s=sf+x.sfg=5.5606 kJ/kg-K

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