Answer to Question #123820 in Mechanical Engineering for sreeju

Question #123820
A 220V,10A dc energy meter is tested at its marked ratings. The resistance of
pressure coil is 9900ohm and that of current coil is 0.5ohm .Calculate the power consumed
when testing the meter with
(i).Direct loading arrangements
(ii).Phantom loading with current circuit excited by a 6V battery
Expert's answer


220v, 10A dc energy meter

Pressure coil resistance 9900 ohm

Current coil rating 0.5 ohm

i) Direct loading arrangements

by pressure coil in parallel

Ppressure coil = v2/R = 2202/9940 = 11 watts

Power consumed by current coil (in series)

220*10 = 2200 w

Total power (direct loading)

2200 + 11 = 2211 w

ii) Phantom loading

In this current coil is excited separately and pressure coil also Thus, power consumed by pressure coil = v2/R = 2202/9940 = 11 w

But power consumed by current coil = v*i = 6*10= 60w

Total = 60 + 11= 71w

Therefore, phantom loading consume less power than direct loading

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!


Assignment Expert
23.12.20, 11:40

Dear roshin,
You're welcome. We are glad to be helpful.
If you liked our service please press like-button beside answer field. Thank you!

22.12.20, 10:43

it is veryy nice that you r helping people to get the answers unlike other websites which first ask to register. very good ...
very nice work, its simple and short...

Leave a comment

Ask Your question

New on Blog