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# Answer to Question #120400 in Mechanical Engineering for Alwin wilson

Question #120400
An accelerometer is measuring a structure as described below: Damping ratio of accelerometer = 0.65 Highest frequency measured by the accelerometer = 6000 hz Natural frequency of the accelerometer = 18000 hz What is the percentage error in the accelerometer at the highest frequency it can measure? (Type in a two-decimal number that represents a percentage)
1
2020-06-10T07:51:10-0400

For finding the error in measurement we can find, "\\zeta=0.65" ,"f=6,000,f_n= 18,000"

"E+1 =\\frac{1}{(1-\\frac{\\omega}{\\omega_n}^2)^2} + (\\frac{2 \\zeta \\omega }{\\omega_n})^2"

"E+1 =\\frac{1}{(1-\\frac{6000}{18000}^2)^2} + (\\frac{2 \\times 0.65 \\times 6000 }{18000})^2"

E+1 = 1.2656 + 0.1877

E= 0.4533

E= "45.33 %" % this is the error percentage

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