Answer to Question #115774 in Mechanical Engineering for Smith

Question

Air initially at 75 psia and 65 0F is compressed to a final pressure of 300 psia and temperature of 320 0F. Find the polytropic exponent for the process.

Answer 1

Here in the given equation it is given that ,

we know that for polytropic process

4.923=

On taking log both sides

log(4.923)=

0.692n=(n-1)0.602

0.692 n = 0. 602 n - .602

0.09 n= -.602

n= - 6.68 here n is the polytropic exponent

but for real condition polytropic exponent can not be negative