Let A be the % live bacteria,
As per the question it is given as the % live bacteria is given as
...........(i)
If it has to decrease 5% of live bacteria then temprature changes by
0.95 A= 30 ....................(ii)
from (i) and (ii)
we get
0.95 =
log(0.95)=
T1=- 44.90T So here temperature should be decrease by 44.90 0C
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