Answer to Question #111208 in Mechanical Engineering for lukas v

Question

A circular tank with a diameter at the bottom of D 20 m and with vertical walls been filled with a flow of 240 m3/h. what will be the increase of the tank depth after 15 minutes, assuming a constant flow during this period of time?

Answer 1

Volume of tank=$\pi r^2h ,$ h= depth of tank and the dia of tank is =20m so radius of tank is 10 m .

Now, flow rate is constant =Q= 240 $\frac{m^3}{h}$

and flow is for 15 min means $times= \frac{1}{4} \times 240 = 60 m^3$

SO, change in volume= dV

$\pi r^2 (h_2-h_1)= 60$

change in depth or increase in depth= $\frac{60}{3.14\times 10\times 10}$ = 0.19 m