Answer to Question #275119 in Electrical Engineering for This

Electrical Engineering

Question #275119

https://ibb.co/VxHH60g

Expert's answer

Solution:

The secondary voltage is

"V_2=7200\/30=240\\text{ V}."

The current in the secondary coil is

"I_2=P\/V_2=25000\/240=104\\text{ A}."

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