Question #261749

1. Two sides of a square are on the line x + 10y – 10 = 0 and x + 10y – 5 = 0. Find the area of the square.

Expert's answer

The distance between two parallel lines "ax+by+c=0" and "ax+by+d=0"

"l=\\frac{|c-d|}{\\sqrt{a^2+b^2}}"

So, we have "l=\\frac{|c-d|}{\\sqrt{a^2+b^2}}=\\frac{|-10-(-5)|}{\\sqrt{1^2+10^2}}=0.4975"

The area of the square "A=0.4975^2=0.2475" . **Answer**

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