Answer to Question #245828 in Electrical Engineering for jinbitchon

Question #245828

Two capacitors C1 and C2 of 1μf and 3μf are connected in parallel

across a voltage supply. At a particular instant when the applied

voltage is increasing positively, the two capacitors together draw a

current of 4A. Find the instantaneous rate of increase of potential

across them. 


1
Expert's answer
2021-10-04T04:55:30-0400

Given

C1= 1uF

C2= 3uF

are connected in parallel

Total capacitance C= C1+C2=(1+3)uF=4 uF

dV/dt= I/C

= 4* 10-6/4=1*10-6

dV/dt=10-6 volt/time


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