Answer to Question #245826 in Electrical Engineering for jinbitchon

Question #245826

The oil dielectric to be used in a parallel plate capacitor has a

relative permittivity of 2.3 and the maximum working potential

gradient in the oil is not to exceed 104 V/m. Calculate the

Approximate plate area required for a capacitance of 0.0003μF,the

Maximum working voltage being 10,000 volts.

Expert's answer

On connecting the two given capacitors, let the final voltage be V.

If capacity of capacitor without the dielectric is C, then the charge on this capacitor is q1​=CV

The other capacitor with dielectric has capacity εC.

Therefore, charge on it is q2​=εCV

As ε=αV, therefore q2​=ε=αV

The initial charge on the capacitor (Without dielectric)

that was charged is q0​=CV0​

From the conservation of charge, q0​=q1​+q2​

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