Answer to Question #242630 in Electrical Engineering for pawan

Question

The 8-bit registers R1, R2, R3, and R4 initially have the following values:

R1 - 1111 0010, R2- 1 1 1 1 1 1 1 1 , R3- 1011 1001 , R4 1 1 101010

Determine the 8-bit values in each register after the execution of the following sequence of

microoperations.

R1 <-R1 + R2

R3<- R3 ^ R4, R2 <- R2 + 1

R1 <- R1 – R3

Answer 1

The best way to dtermine this is by understanding that each registrer is arranged stiucturally

based on the needs. In this case, we can compute this as follows:

AR = AR + BR Add BR to AR storing answer in AR CR = CR ^ DR , BR = BR + 1 AND DR to

CR, INC BR AR = AR – CR Subtract CR from AR AR + BR = 11110010 + 11111111

(1)11110001 AR = 11110001 CR ^ DR = 10111001 ^ 11101010 10101000 CR = 10101000 BR

+ 1 = 00000000 BR = 00000000 AR – CR = 11110001 – 10101000 = 11110001 + ~(10101000)

+ 1 = 11110001 + 01010111 + 1 = 11110001 + 01010111 + 00000001 01001001 Therefore AR

= 01001001