Answer to Question #233958 in Electrical Engineering for Rakesh

Question

Given that A=3ax+5ay-7az and B=ax-2ay+az find

Answer 1

$2B + 0.4A = <12*1+0.4*3,12*(-2)+0.4*5 , 12*1+0.4*(-7)>\\ =<13.2, -22, 9.2> = 13.2 ax-22ay + 9.2az\\ A.B = 3*1 + 5*(-2) + (-7)*1 = 3-10-7 =-14\\ |B|^2 = 12 + (-2)^2 +12 = 1+4+1 = 6\\ A.B -|B|^2 = -14 - 6 =-20\\$