Question #232180

Simplify the following boolean expression, using four-variable maps:

AB'C + B'C'D' + BCD + ACD' + A'B'C + A'BC'D

Expert's answer

"\\def\\arraystretch{1.5}\n \\begin{array}{c:c:c:c:c}\nAB\/CD & 00 & 01 & 11 & 10\\\\ \\hline\n 00 &1 & &1&1 \\\\ \\hline\n 01& &1 &1\\\\ \\hline\n11& & &1&1\\\\ \\hline\n10&1 & &1&1\\\\\n\\hdashline\n\\end{array}"

Using the karnaugh map.

The boolean is reduce to

"A'BD+CD+B'D'+B'C"

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