Answer to Question #229609 in Electrical Engineering for Priya

Question

A combinational circuit has four inputs (A,B,C,D), which represent a binarycoded-decimal digit. The

circuit has two groups of four outputs - S,T,U,V(MSB digit) and W,X,Y,Z.(LSB digit)Each group

represents a BCD digit. The output digits represent a decimal number which is five times the input

number. Illustrate the minimum expression for all the outputs?

Answer 1

A

B

C

D

Output (per 5 Inputs )

S

T

U

V

W

X

Y

Z

0

0

0

0

50=00

0

0

0

0

0

0

0

0

0

0

0

1

51=05

0

0

0

0

0

1

0

1

0

0

1

0

52=10

0

0

0

1

0

0

0

0

0

0

1

1

53=15

0

0

0

1

0

1

0

1

0

1

0

0

54=20

0

0

1

0

0

0

0

0

0

1

0

1

55=25

0

0

1

0

0

1

0

1

0

1

1

0

56=30

0

0

1

1

0

0

0

0

0

1

1

1

57=35

0

0

1

1

0

1

0

1

1

0

0

0

58=40

0

1

0

0

0

0

0

0

1

0

0

1

59=45

0

1

0

0

0

1

0

1

We first established that the connection between input and output is X5:

Therefore, the 4 outputs ABCD gives us the minimal expression of the provided inputs

However, codes such as 1010 and 1111 become null and do not come up as inputs as shown

above.