Question #226223

2.1 The per-phase parameters for a 60 Hz, 200 km long transmission line are

Expert's answer

The total resistance "= 2 \\pi fL= 2\\pi*60*310.8= 117.16 \\Omega\\\\"

Capacitance resistance "X_c= \\frac{1}{jwC}=- \\frac{j}{2 \\pi fC}=- \\frac{j}{2 \\pi *60*1.477 \\mu F}"

Therefore admittance "Y= \\frac{1}{X_c}=2 \\pi fC=2 \\pi *60*1.477*10^{-6}= 0.0005565"

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