Answer to Question #214001 in Electrical Engineering for Fredy

Question #214001

How can we calculate the internal resistance of a wheatstone brigde given that Resistance 1=Resistance 2=Resistance 3=Resistance 4=1000 ohms and a galvanometer can detect as low as 0.1 milliamperes?


1
Expert's answer
2021-07-07T09:51:02-0400

Calculating the internal resistance across the galvanometer

R1 and R2 are in parallel, so their effective resistance is

R3 and R4 are also in parallel. Their effective resistance is

Internal resistance is 1000ohms

R12 is now in series with R13 to give the value of the internal resistance


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