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Answer to Question #212685 in Electrical Engineering for Haidi

Question #212685

In a P-Type semiconductor, the Fermi level in 0.3 eV above the valance band at a room temperature of 300 oK. Determine the new position of the Fermi level for temperature of a (350 oK) and (b) 400 oK.

1
2021-07-04T19:54:02-0400

"E_F=E_V+KT\\ln(\\frac{N_v}{N_A})\\\\\nE_F-E_V=0.3eV\\\\\nT=300\\degree{K}\\\\\nE_F-E_V=KT\\ln(\\frac{N_v}{N_A})\\\\\n0.3=300K\\ln(\\frac{N_v}{N_A})\\\\\nK\\ln(\\frac{N_c}{N_A})=\\frac{0.3}{300}\\\\\nK\\ln(\\frac{N_c}{N_A})=0.001\\\\\n(a)\\\\\nT=350\\degree{K}\\\\\nE_F-E_V=KT\\ln(\\frac{N_v}{N_A})\\\\\nE_F-E_V=350K\\ln(\\frac{N_v}{N_A})\\\\\nE_F-E_V=350\\times 0.001\\\\\nE_F-E_V=0.35eV\\\\\n(b)\\\\\nT=400\\degree{K}\\\\\nE_F-E_V=KT\\ln(\\frac{N_v}{N_A})\\\\\nE_F-E_V=400K\\ln(\\frac{N_v}{N_A})\\\\\nE_F-E_V=0.40eV"

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