Question #206768

The saturation current will be the twice of the diode current. and contact potential of the diode is 33 Volt. calculate the temperature.

Expert's answer

Ideal diode equation is given by

I=I_o(e^{\frac {qV}{kT}}-1)

Diode current=I

Saturation current= I_o

Electron charge=q

Contact voltage=V

Boltzmann's constant=k

Temperature= T

Making T the subject of the formula

T= \frac {\frac {qV}{k}}{\ln(\frac{I}{I_o}+1)}

q=1.6 \times 10^{-19}C

V=33v

k= 1.38 \times 10^{-23}m^2kgs^{-2}K^{-1}

I_o=2\times I

T= \frac {\frac {1.6 \times 10^{-19} \times 33}{1.38 \times 10^{-23}}}{\ln(\frac{I}{2 \times I}+1)}

T= \frac{382608.69}{\ln1.5}

T=943629K

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