Answer to Question #202745 in Electrical Engineering for tafadzwa

Question #202745

The metal bar is AB =10mm, DA=18mm, BC =220cm and the resistivity of the metal is 0,012 micro ohms. what is its tip to tip resistance


1
Expert's answer
2021-06-08T06:53:02-0400

Resistance of a conductor of uniform section "S" is "R =\\frac{\\rho l}{S}", where "\\rho" is electrical resistivity, "l" is length.

The area of the cross section of the bar is "S = 10 \\cdot 10^{-3} m \\cdot 18 \\cdot 10^{-3} m = 1.8 \\cdot 10^{-4} m^2", and the length is "l = 2.2 m". Hence, the resistance is:

"R = \\frac{0.012 \\cdot 10^{-6} \\Omega \\cdot m \\ 2.2 m\\cdot }{1.8 \\cdot 10^{-4} m^2} \\approx 1.5 \\cdot 10^{-4} \\Omega".


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