For low-pass RL filter with R = 20 Ω and L = 2 mH , the corner frequency is:
Select one:
a. 3,979 Hz
b. 796 Hz
c. 1,592 Hz
d. 19,894 Hz
e. 7.958 Hz
fc=R2πL=202π∗2∗10−3=1591.5Hzf_c=\frac{R}{2 \pi L}=\frac{20}{2 \pi *2*10^{-3}}=1591.5 Hzfc=2πLR=2π∗2∗10−320=1591.5Hz
∴\therefore∴ Correct option is C
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