Question #189569

A 6-pole generator has a lap-wound armature with 40 slots with 20 conductors per slot.The flux per pole is 25mWb.The terminal voltage is 288v and the voltage regulation of the generator is 4%. Determine the speed of the generator.

Expert's answer

"E_g=\\frac{P\\phi NZ}{60A}"

"E_g=V+0.04V=288+0.04\\cdot288=299.52\\ (V)"

"N=\\frac{60AE_g}{P\\phi Z}=\\frac{60\\cdot6\\cdot 299.52}{6\\cdot0.025\\cdot (40\\cdot20)}=682\\ (rpm)" . **Answer**

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