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# Answer to Question #174866 in Electrical Engineering for Aswin

Question #174866

The full-load efficiency of a 400 V, 3-phase, 6 pole induction motor is 85%. It draws a line current of 80 A at 0.8 power factor lagging when it delivers full-load at 5% slip. Calculate the shaft output and shaft torque.

1
Expert's answer
2021-04-01T01:09:11-0400

The power of the motor is

"P=VI\\cos\\phi."

The mechanical power output is

"P_m=\\eta P=\\eta VI\\cos\\phi."

The synchronous frequency of a 6-pole motor is 1000 min-1, which corresponds to angular

velocity of

"\\omega=\\frac{2\\pi n}{60}."

The angular velocity of the shaft is

"\\omega_s=w(1-s)=\\frac{\\pi n}{30}(1-s)."

The shaft torque:

"T=\\frac{P}{\\omega_s}=\\frac{30\\eta VI\\cos\\phi}{\\pi n(1-s)}=122.4\\text{ N}\u00b7\\text{m}."

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