Question #166132

Draw the phasor diagram and find the sum of the currents: i1=141.42 Sin(t + /2) , i2

= -70.71 Cos t , i3= 50 ej/3 , i4=100 -2/3 and i5= 50 (Cos /3 + j Sin/3)

Expert's answer

the sum of the currents = 50 (Cos /3 + j Sin/3

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