Answer to Question #165822 in Electrical Engineering for Enthada Nokkunne

Question #165822

Draw the phasor diagram and find the sum of the currents: i1=141.42 Sin(ωt + /2) , i2 = -70.71 Cosωt , i3= 50 e^jπ/3 , i4=100 -2π/3 and i5= 50 (Cos π/3 + j Sinπ/3) 


1
Expert's answer
2021-03-01T02:13:50-0500

sum of the currents=42 Sin(ωt + /2)+100 -2π/3


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