Answer to Question #117820 in Electrical Engineering for Sachin Kumar

Question #117820
A 11 kV, 50 Hz, star connected cylindrical rotor alternator gave the following data on open circuit:
If in Amp 0 10 15 20 31 39 50 55
Ef in kV 0 5.00 7.50 9.00 11.00 12.00 12.80 13.40
An excitation of 20 A was required to circulate a full load current of 160 A on short-circuit. For zeropower factor test, an excitation current 66 A was required to circulate 1.25 times the full load current at 11 kV. Estimate the voltage regulation at full load 0.8 p.f lagging by z.p.f method. Neglect armature resistance.
1
Expert's answer
2020-05-27T14:07:19-0400
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