Question #117809

A salient –pole synchronous generator has the following per-unit parameters; Xd = 1.00, Xq=

0.60, ra= 0.02Ω. If the generator is delivering rated KVA at rated voltage and at 0.8 p.f leading,

compute the power angle and the excitation e.m.f. Draw the phasor diagram also.

0.60, ra= 0.02Ω. If the generator is delivering rated KVA at rated voltage and at 0.8 p.f leading,

compute the power angle and the excitation e.m.f. Draw the phasor diagram also.

Expert's answer

As per the given in the question,

"X_d =1"

"X_q=0.6"

"r_a=0.02\\Omega"

Power angle=?

Excitation emf=?

We know that "V\\cos \\delta =X_d I----(i)"

and "V\\sin \\delta =X_q I---(ii)"

From (i) and (ii)

"\\tan \\delta =\\frac{X_q}{X_d}=\\frac{0.6}{1}"

"\\delta =\\tan ^{-1}(0.6)=30.96^\\circ"

"E=\\sqrt{(Ir_a)^2+(IX_d)^2}"

"\\Rightarrow E =\\sqrt{I^2+0.0004I^2}"

But here the value of I is not given in the question, so it can not be determined

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