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# Answer to Question #117809 in Electrical Engineering for Sachin Kumar

Question #117809
A salient –pole synchronous generator has the following per-unit parameters; Xd = 1.00, Xq=
0.60, ra= 0.02Ω. If the generator is delivering rated KVA at rated voltage and at 0.8 p.f leading,
compute the power angle and the excitation e.m.f. Draw the phasor diagram also.
1
2020-06-10T07:51:19-0400

As per the given in the question,

"X_d =1"

"X_q=0.6"

"r_a=0.02\\Omega"

Power angle=?

Excitation emf=?

We know that "V\\cos \\delta =X_d I----(i)"

and "V\\sin \\delta =X_q I---(ii)"

From (i) and (ii)

"\\tan \\delta =\\frac{X_q}{X_d}=\\frac{0.6}{1}"

"\\delta =\\tan ^{-1}(0.6)=30.96^\\circ"

"E=\\sqrt{(Ir_a)^2+(IX_d)^2}"

"\\Rightarrow E =\\sqrt{I^2+0.0004I^2}"

But here the value of I is not given in the question, so it can not be determined

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