# Answer to Question #232885 in Civil and Environmental Engineering for Bae

Question #232885
A 50 m steel tape is of standard length under a pull of 5.5 kg when supported throughout its entire length. the tape weighs 0.05 kg/m, has a cross sectional area of 0.04 sq.cm and being made steel, it's modulus of elasticity is 2.10x10^6 kg/cm2. this tape was used in the field to measure a distance that was determined to be 458.650 m. at the time the measurement was made, the constant pull applied was 8 kg with the tape supported only at its end points. determine the correct length of the line.
1
2021-09-04T01:01:17-0400

l = Length of tape = 50 m

L = Length of measurement = 458.650 m

Pm = Pull at the time of measurement = 8 kg

Po = Pull at the time of s tan dardization = 5. 5 kg

w = Weight of tape = 0.05 kglm

A = Cross — sectional area of tape = 0.04 cm2

E = Modulus of Elasticity = 2. 1 x 106 Kg/cm

To find

Correction measure line;

Cp = Correction measure line due to tension

Cp=(Pm—Po)L/AE

Cp = AE (8 — 5.5)x458.650/0.04x2.10x106

Cp = 0.014 m (+ve)

Length of one tape is 50 m, so for measurement of 458. 650 in distance,

9 tapes + 8. 650 m = 9 x 50 + 8.650 = 458. 650 m

lr= Remaining length = 8. 650 m

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