Question #231200

Compute for the distance between the theodolite and the subtense bar if the subtended angle observed is 1degree 24 minutes and 32 seconds.

Expert's answer

Distance = "H= \\frac{D}{2} \\cot \\frac{\\alpha}{2}"

"\\frac{\\alpha}{2}= \\frac{1^0+(\\frac{24}{60})^0+(\\frac{32}{60*60})^0}{2}=\\frac{\\frac{317}{225}}{2}=0.70444"

If D = 2 m

"H= \\frac{2}{2} \\cot 0.70444= 1.17659 m"

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