Answer to Question #226703 in Civil and Environmental Engineering for Rexie

Question

A ball is released from a window that is 10 meters above the ground. When the ball leaves your hand, it is moving 8m/s at an angle 300 below the horizontal. Ignoring the effect of air resistance, how far horizontally from the window will the ball hit the ground?

Answer 1

$U_x=ucosα=8*cos30=6.92820m/s\\ U_y=usinα=8*sin30 =4m/s\\ Y=usinα*t+\frac{1}{2}gt^2\\ 10=4t+6.92820t^2\\ Solving \space for \space t=0.95sec\\ Horizontal \space distance=U_x*t=6.92820*0.95=6.58179m$