Answer to Question #215706 in Civil and Environmental Engineering for Query

Question #215706
A solid shaft 100 mm in diameter is subjected simultaneously to an axial compressive force of 50 kN and to a torque that twist through an angle of 1.5
1
Expert's answer
2021-07-12T03:36:39-0400

If we were to find the torque

If "G_{steel} = 85 GPa" we can find the torque of the twist.

"\\frac{T}{J}=\\frac{G \\theta}{L} \\implies T= \\frac{G \\theta}{L}J\\\\\nT= \\frac{ 85*10^9*\\frac{1.5\\pi}{180}}{1}*\\frac{\\pi}{32}*0.1^4\\\\\nT=21.84678 kNm"



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